How do I assemble a console application with Maven without unpacking all dependencies?

Suppose I have the following directory layout in a Maven project:

src/
|-- main
|   |-- bin
|   |   |-- run.cmd
|   |   `-- run.sh
|   |-- etc
|   |   |-- common-spring.xml
|   |   |-- log4j.xml
|   |   `-- xml-spring.xml
|   `-- java
|       `-- com
...

I would like to build a zip file that, when unzipped, produces something like this:

assembly
|-- bin
|   |-- run.cmd
|   `-- run.sh
|-- etc
|   |-- common-spring.xml
|   |-- log4j.xml
|   `-- xml-spring.xml
`-- lib
    |-- dependency1.jar
    |-- dependency2.jar
...

where `run.xx' are executable shell scripts that will call my main application and put all dependencies on the classpath.

Is this possible with some of the `official' Maven plugins, e.g. maven-assembly-plugin?

Asked by: Emily341 | Posted: 21-01-2022

Answer 1

I use the AppAssembler plugin to get something similar. Example:

...
<build>
<plugins>
  <plugin>
    <groupId>org.codehaus.mojo</groupId>
    <artifactId>appassembler-maven-plugin</artifactId>
    <configuration>
      <programs>
        <program>
          <mainClass>com.acme.MainClass</mainClass>
          <name>app</name>
        </program>
      </programs>
    </configuration>
  </plugin>
</plugins>

Answered by: Victoria804 | Posted: 22-02-2022

Answer 2

I've used the maven-assembly-plugin to acheive something similar in a project. I wanted a zip file to be built during the package phase, instead of manually calling assembly:assembly. Here's what I came up with:

/src/assemble/distribution.xml:

<assembly>
  <id>distribution</id>

  <!-- specify the output formats -->
  <formats>
    <format>zip</format>
  </formats>

  <!-- include all runtime libraries in the /lib folder of the output file -->
  <dependencySets>
    <dependencySet>
      <outputDirectory>/lib</outputDirectory>
      <scope>runtime</scope>
    </dependencySet>
  </dependencySets>

  <fileSets>
    <!-- include all *.jar files in the target directory -->
    <fileSet>
      <directory>target</directory>
      <outputDirectory></outputDirectory>
      <includes>
        <include>*.jar</include>
      </includes>
    </fileSet>

    <!-- include all files in the /conf directory -->
    <fileSet>
       <outputDirectory></outputDirectory>
       <includes>
        <include>conf/**</include>
       </includes>
    </fileSet>
  </fileSets>

</assembly>

/pom.xml

...

        <plugin>
            <artifactId>maven-assembly-plugin</artifactId>

            <configuration>
                <descriptors>
                    <descriptor>src/assemble/distribution.xml
                    </descriptor>
                </descriptors>
            </configuration>

            <!-- append assembly:assembly to the package phase -->
            <executions>
                <execution>
                    <phase>package</phase>
                    <goals>
                        <goal>assembly</goal>
                    </goals>
                </execution>
            </executions>

        </plugin>

...

Answered by: Brooke833 | Posted: 22-02-2022

Answer 3

The maven-assembly-plugin can also copy the dependencies into your assembly, by including something like the below in your assembly descriptor file:

<dependencySets>
    <!-- Copy dependency jar files to 'lib' -->
    <dependencySet>
        <outputDirectory>lib</outputDirectory>
        <includes>
            <include>*:jar:*</include>
        </includes>
    </dependencySet>
</dependencySets>

Answered by: Oliver111 | Posted: 22-02-2022

Answer 4

The appassembler generates the 'run.xx' files for you.

If you have already created the shell scripts yourself you can use the maven-assembly-plugin to create the zip file. To gather the dependencies you can use maven-dependency-plugin.

Answered by: Aldus164 | Posted: 22-02-2022

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