Answer 1

My guess is you are actually doing something like:

System.out.println("" + size + estimated); 

This expression is evaluated left to right:

"" + size        <--- string concatenation, so if size is 3, will produce "3"
"3" + estimated  <--- string concatenation, so if estimated is 2, will produce "32"

To get this to work, you should do:

System.out.println("" + (size + estimated));

Again this is evaluated left to right:

"" + (expression) <-- string concatenation - need to evaluate expression first
(3 + 2)           <-- 5
Hence:
"" + 5            <-- string concatenation - will produce "5"

Answered by: Arthur549 | Posted: 01-03-2022

Answer 2

I suspect you're not seeing what you think you're seeing. Java doesn't do this.

Please try to provide a short but complete program which demonstrates this. Here's a short but complete program which demonstrates correct behaviour, but with your "wrong" code (i.e. a counterexample).

import java.util.*;

public class Test
{
    public static void main(String[] args)
    {
        Vector speeds = new Vector();
        speeds.add("x");
        speeds.add("y");

        long estimated = 1l;
        long time = speeds.size() + estimated;
        System.out.println(time); // Prints out 3
    }
}

Answered by: Thomas772 | Posted: 01-03-2022

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