Catching exceptions with tomcat and a servlet
I have set-up tomcat to catch all my exceptions and pass them to a servlet with the following in web.xml.
<servlet-mapping>
<servlet-name>exception</servlet-name>
<url-pattern>/exception</url-pattern>
</servlet-mapping>
<error-page>
<exception-type>java.lang.Exception</exception-type>
<location>/exception</location>
</error-page>
This works fine and I have the servlet logging some information and forwarding to a jsp. However I want to log the URI which caused the exception to be thrown and when I call request.getRequestURI() I get /exception which is my servlet path that's handling logging the exception. How can I get the original URI that caused the exception?
Asked by: Ryan141 | Posted: 23-01-2022
Answer 1
You can get the original uri with
request.getAttribute("javax.servlet.forward.request_uri")
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